A mother is twice as old as her son. If 20 years ago, the age of the mother was 10 times the age of the son, what is the present age of the mother?
39 Years
40 Years
45 Years
47 Years
The correct answer is 45 years
Explanation:
Let age of the son=x
mother's age=2x
According to the question,
20 years ago,
10(x-20)=2x-20
10x-200=2x-20
10x-2x=200-20
8x=180
x=180/8
x=22.5 Years
Therefore the Present age of the mother is 22.5*2= 45 Years.
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